Dimensions of an O'Neill cylinder with gravity and coriolis force like surface of Earth

What would be the diameter and rotational speed of an O'Neill cylinder on the inside surface of which centrifugal and coriolis forces are equal to "gravity" and coriolis force on the surface of Earth at sea level?

Notes:

• "Gravity on Earth" (in quotation marks) here means the sum of gravitation and centrifugal force. Assume that the sum of these forces results in an acceleration of 1 g.

• Place on Earth for the coriolis force can be any latitude between the equator and 60°. Pick one you find represents living on Earth well, e.g. 45°.

• On Earth, there is a slight difference in "gravity" between my feet and my head. This difference must be the same on the inside surface of the O'Neil cylinder.

• You may ignore the gravitation of the cylinder's wall. If you want to estimate it, the wall of the cylinder is no thicker than 35 km and composed like the crust of the Earth.

• Do not forget the coriolis force!

• Your answer may prove that my requirements cannot be met! Just explain how far one or multiple parameters deviate from the requirement (e.g. "coriolis force would be x times larger than on Earth").

• The dimensions of this O'Neill cylinder aren't fixed to that of O'Neill's or anyone else's original design. You may change the radius or any other measure to meet the requirements as closely as possible. The cylinder can be as big as the Earth or bigger, if it needs to be. 1 g of "gravity" and a head-foot-difference of gravity like that of Earth are the requirements that must be met.

posted over 5 years ago

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