How would I calculate how much of Venus would be covered in water if 8.8E16 m^3 was added to its surface?
If $8.8 \times 10^{16} m^3$ of water volume is added to the surface of Venus, how would I calculate how much of Venus would be covered in water?
The land of Venus has its topographical features with plains, valleys, high lands, etc, therefore water would not be distributed evenly across the surface. Water will obviously find its way to the lowest ground available.
Therefore, knowing only the water volume wouldn't help unless you know how the volume is distributed over the surface of Venus. Given topographical features of Venus, how would we calculate the distribution of water volume over the surface?
Other things to consider
- In answering the question, you could safely ignore the atmosphere, and if it matters, assume the atmosphere is earth-like.
- The topographic map of venus is available on the net, but frankly I have no idea what to do on them. I have no experience nor expertise on working with topographical map, which probably needs some kind of geological degree or perhaps computer degree to make sense of the map. So it would be very helpful to have an answer that provides a more understandable interpretation of the map, in a form usable for calculations knowing only the extra volume of the water. This is not an absolute requirements.
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