Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

How is the visual luminosity of a star calculated?

+0
−0

My idea is a planet that orbits a red dwarf at a distance in which the apparent magnitude of this seen from the planet is the same as that of the sun seen from Earth. Does this mean that the daylight on the planet will be as intense as that of Earth?

I know that the red dwarfs emit most of their energy in the infrared spectrum, invisible to humans, therefore, a planet located at a distance from it in which it receives the same amount of energy as that received by the Earth of the sun, it will be darker, despite having the same equilibrium temperature. My question is, is the apparent magnitude measured considering the entire electromagnetic spectrum or just the visible spectrum?

If it is not enough for the star to have the same apparent magnitude as the sun so that the daylight of the planet is the same as that of the Earth, how is its visual magnitude calculated?

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.
Why should this post be closed?

This post was sourced from https://worldbuilding.stackexchange.com/q/154245. It is licensed under CC BY-SA 4.0.

0 comment threads

0 answers

Sign up to answer this question »