Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

How do you determine placement of multiple lunar bodies in the night sky?

+0
−0

One of the worlds I'm building has three moons in 1:2:4 resonance, with the full moons syncing up once a cycle, meaning all three are full at different times but at the same time when the moon with the longest orbit completes a single orbit.

What I've been thinking about lately though is where they would appear in the sky based on their orbit and phase, especially after finding the following image:

enter image description here

Now, as far as I'm aware, the moon appears in roughly the same place to an observer because both the moon and earth are in constant motion. However, with multiple lunar bodies, I get the feeling this movement will have a more pronounced effect on observation.

Essentially what I'm trying to figure out is where these moons would appear in relation to one another in the night sky and how much, if at all, they would appear to shift to an observer.

History
Why does this post require moderator attention?
You might want to add some details to your flag.
Why should this post be closed?

This post was sourced from https://worldbuilding.stackexchange.com/q/101690. It is licensed under CC BY-SA 3.0.

0 comment threads

0 answers

Sign up to answer this question »