Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Is my celestial coordinate system efficient?

+0
−0

I want to know whether or not my starship's cordinate system is efficient or not. Soon after my race flew into the stars, we realised we needed to be able to tell where we were. We need coordinate systems. This particular system has an angle and a distance to define positions in space. The angle is a quaternion rotation from the sun (to avoid gimbal lock with euler coordinates) and a distance in light years along that angle. The 'right' of the sun is Earth's position from the sun on January 1st. Is this a good way of defining a position in the context of our spiral arm of the galaxy? What problems will I face using this system?

EDIT:

The 'right' of the sun specifies a basis for the Quaternion rotation.

January 1st 12 am is a unified time across all of Earth

A lot of people seem to be getting confused here. Quaternion rotation specifies an angle in 3D space. It defines any 3 dimensional direction.

History
Why does this post require moderator attention?
You might want to add some details to your flag.
Why should this post be closed?

This post was sourced from https://worldbuilding.stackexchange.com/q/91555. It is licensed under CC BY-SA 3.0.

0 comment threads

0 answers

Sign up to answer this question »