Post History
On Earth, escape velocity is about 11 km/s, or 11,000 m/s. Assuming the opponent weighs around 70 kg (maybe more), that's a kinetic energy of at least $$\text{KE}=\frac{1}{2}mv^2=\frac{1}{2}\cdot70...
Answer
#1: Attribution notice removed
by
System
·
2020-06-01T14:13:52Z (over 4 years ago)
Source: https://worldbuilding.stackexchange.com/a/79405 License name: CC BY-SA 3.0 License URL: https://creativecommons.org/licenses/by-sa/3.0/