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That's no planet! Let's say that the radius is $18R_{\oplus}$, where $R_{\oplus}$ is Earth's radius. The volume will then be $$\frac{4}{3}\pi(18R_{\oplus})^3\bar{\rho}=5832\left(\frac{4}{3}\pi R_{...
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#1: Attribution notice removed
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System
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2020-06-01T14:13:52Z (over 4 years ago)
Source: https://worldbuilding.stackexchange.com/a/74965 License name: CC BY-SA 3.0 License URL: https://creativecommons.org/licenses/by-sa/3.0/