That's no planet! Let's say that the radius is 18R⊕, where R⊕ is Earth's radius. The volume will then be $$\frac{4}{3}\pi(18R_{\oplus})^3\bar{\rho}=5832\left(\frac{4}{3}\pi R_{...
posted 8y ago by HDE 226868 · last activity 6y ago by HDE 226868
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