Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Multiple moons orbiting a gas giant: How would I calculate how long it appears for a closer moon to orbit the planet from a further-out moon?

+0
−0

I have a habitable moon orbiting a gas giant, and there is another moon orbiting the planet on a closer orbit. The cultures on the near-side of the further, habitable moon use the transit of the closer moon across the planet for timekeeping, but I don't know how to figure out how long it appears to take the closer moon to orbit the planet from the surface of the further moon. It takes the closer moon (161,600 km from planetary center) 19.85 hours to orbit the planet, and the further moon (340,800 km from planetary center) 60.57 hours to do the same. They orbit in the same direction and both have very low eccentricity. Is there some way to numerically model the two moons' orbits around the planet so that I can see how fast one moon appears to travel relative to the other?

History
Why does this post require moderator attention?
You might want to add some details to your flag.
Why should this post be closed?

This post was sourced from https://worldbuilding.stackexchange.com/q/59904. It is licensed under CC BY-SA 3.0.

0 comment threads

0 answers

Sign up to answer this question »