Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

How large could a planetary diamond be?

+0
−0

Back in the days when men were real men, women were real women, and small, furry creatures from Alpha Centauri were real small furry creatures from Alpha Centaury, an obscenely rich woman decided she wanted to have the biggest diamond of all.

Realizing that this would mean a diamond of planetary size, she went to Magrathea and ordered it there. She had only two conditions: It should be a perfect single-crystalline diamond, and it should be impossible to make a larger one, because trying to do so would make it stop being a perfect diamond. Of course, Magrathea delivered what was ordered.

Now as long as the diamond planet was in the hyperspace construction halls of Magrathea, all natural laws could be effectively put out of force as needed, but as soon as the planet was put into normal space, it was under the full force of the laws of physics.

Now my question: How large was the diamond which was ultimately delivered by Magrathea?

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.
Why should this post be closed?

0 comment threads

0 answers

Sign up to answer this question »