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Using Kepler's third law, I get $$a=\sqrt[3]{\frac{P^{2}G\times (M+M)}{4{\pi }^2}}=5.32\times {10}^4\text{ kilometers}$$ where $a$ is the semi-major axis, $P$ is the time it takes the planets to orbit each ...

posted 8y ago by HDE 226868‭  ·  last activity 8y ago by HDE 226868‭